## Engage NY Eureka Math 4th Grade Module 3 Lesson 33 Answer Key

### Eureka Math Grade 4 Module 3 Lesson 33 Problem Set Answer Key

Question 1.

Ursula solved the following division problem by drawing an area model.

a. What division problem did she solve?

Answer:

Ursula solved division problem of 892 ÷ 4 = 223,

Explanation:

Ursula solved the following division problem by drawing an area model as shown above of (400 + 400 + 80 + 12) ÷ 4 = 892 ÷ 4 as

(100 + 100 +20 +3) = 223.

b. Show a number bond to represent Ursula’s area model and represent the total length using the distributive property.

Answer:

Explanation:

Drawn number bond to represent Ursula’s area model and represented the total length using the distributive property as

= (400 ÷ 4) + (400 ÷ 4) + (80 ÷ 4) + (12 ÷ 4)

= 100 + 100 + 20 + 3

= 223.

Question 2.

a. Solve 960 ÷ 4 using the area model. There is no remainder in this problem.

Answer:

Explanation:

Solved 960 ÷ 4 using the area model as shown above

(960 ÷ 4) = (800 ÷ 4) + (160 ÷ 4) = 200 + 40 = 240.

b. Draw a number bond and use the long division algorithm to record your work from Part (a).

Answer:

Explanation:

Drawn a number bond and used the long division algorithm to record my work from Part (a) as shown above 960 ÷ 4 = 240.

Question 3.

a. Draw an area model to solve 774 ÷ 3.

Answer:

Explanation:

Drawn an area model as shown above for 774 ÷ 3 =

(600 ÷ 3) + (150 ÷ 3) + (24 ÷ 3) = 200 + 50 + 8 = 258.

b. Draw a number bond to represent this problem.

Answer:

Explanation:

Drawn a number bond to represent this problem as shown above (600 ÷ 3) + (150 ÷ 3) + (24 ÷ 3) = 200 + 50 + 8 = 258.

c. Record your work using the long division algorithm.

Answer:

Explanation:

Recorded my work using the long division algorithm as

shown above.

Question 4.

a. Draw an area model to solve 1,584 ÷ 2.

Answer:

Explanation:

Drawn an area model to solve 1,584 ÷ 2 =

(1,400 ÷ 2) + (180 ÷ 2) + (4 ÷ 2) =

700 + 90 + 2 = 792 as shown above.

b. Draw a number bond to represent this problem.

Answer:

Explanation:

Drawn a number bond to represent this problem as shown above 1,584 ÷ 2 = (1,400 ÷ 2) + (180 ÷ 2) + (4 ÷ 2) =

700 + 90 + 2 = 792.

c. Record your work using the long division algorithm.

Answer:

Explanation:

Recorded my work using the long division algorithm as shown above.

### Eureka Math Grade 4 Module 3 Lesson 33 Exit Ticket Answer Key

Question 1.

Anna solved the following division problem by drawing an area model.

a. What division problem did she solve?

Answer:

Anna solved division problem of 747 ÷ 3 = 249,

Explanation:

Given Anna solved the following division problem by drawing an area model of 747 ÷ 3 =

(600 ÷ 3) + (120 ÷ 3) + (27 ÷ 3) = 200 + 40 + 9 = 249.

b. Show a number bond to represent Anna’s area model, and represent the total length using the distributive property.

Answer:

Explanation:

Shown a number bond to represent Anna’s problem representing the total length using the distributive property

as 747 ÷ 3 = (600 ÷ 3) + (120 ÷ 3) + (27 ÷ 3) = 200 + 40 + 9 = 249.

Question 2.

a. Draw an area model to solve 1,368 ÷ 2.

Answer:

Explanation:

Drawn an area model to solve 1,368 ÷ 2 =

(1,200 ÷ 2) + (160 ÷ 2) + (8 ÷ 2) = 600 + 80 + 4 = 684 as shown above.

b. Draw a number bond to represent this problem.

Answer:

Explanation:

Drawn a number bond to represent problem as shown above 1,368 ÷ 2 = (1,200 ÷ 2) + (160 ÷ 2) + (8 ÷ 2)

= 600 + 80 + 4 = 684.

c. Record your work using the long division algorithm.

Answer:

Explanation:

Recorded my work using the long division algorithm as shown above.

### Eureka Math Grade 4 Module 3 Lesson 33 Homework Answer Key

Question 1.

Arabelle solved the following division problem by drawing an area model.

a. What division problem did she solve?

Answer:

Arabelle solved the division problem as 1,828 ÷ 4 =

(1600 + 200 + 28) ÷ 4 = 400 + 50 + 7 = 457.

b. Show a number bond to represent Arabelle’s area model, and represent the total length using the distributive property.

Answer:

Explanation:

Shown a number bond to represent Arabelle’s problem representing the total length using the distributive property

as 1,828 ÷ 4 = (1600 ÷ 4) + (200 ÷ 4) + (28 ÷ 4)

= 400 + 50 + 7 = 457.

Question 2.

a. Solve 816 ÷ 4 using the area model. There is no remainder in this problem.

Answer:

Explanation:

Solved 816 ÷ 4 using the area model as shown above

(816 ÷ 4) = (800 ÷ 4) + (16 ÷ 4) = 200 + 4 = 204.

b. Draw a number bond and use a written method to record your work from Part (a).

Answer:

Explanation:

Drawn a number bond to represent problem as shown above 816 ÷ 4 = (800 ÷ 4) + (16 ÷ 4) = 200 + 4 = 204.

Question 3.

a. Draw an area model to solve 549 ÷ 3.

Answer:

Explanation:

Drawn an area model to solve 549 ÷ 3 =

(300 ÷ 3) + (240 ÷ 3) + (9 ÷ 3) =

100 + 80 + 3 = 183 as shown above.

b. Draw a number bond to represent this problem.

Answer:

Explanation:

Drawn a number bond to represent problem as shown above 549 ÷ 3 = (300 ÷ 3) + (240 ÷ 3) + (9 ÷ 3)

= 100 + 80 + 3 = 183.

Answer:

Explanation:

Recorded my work using the long division algorithm as shown above.

Question 4.

a. Draw an area model to solve 2,762 ÷ 2.

Answer:

Explanation:

Drawn an area model to solve 2,762 ÷ 2 =

(2,000 ÷ 2) + (600 ÷ 2) + (160 ÷ 2) + (2 ÷ 2)

= 1,000 + 300 + 80 + 1 = 1,381 as shown above.

b. Draw a number bond to represent this problem.

Answer:

Explanation:

Drawn a number bond to represent problem as shown above

2,762 ÷ 2 = (2,000 ÷ 2) + (600 ÷ 2) + (160 ÷ 2) + (2 ÷ 2)

= 1,000 + 300 + 80 + 1 = 1,381.

Answer:

Explanation:

Recorded my work using the long division algorithm as shown above.